## Stopwatch in java

Robin just received a stopwatch from her grandfather. Robin’s stopwatch has a single button. Pressing the button alternates between stopping and starting the stopwatch’s timer. When the timer is on, the displayed time increases by 1 every second.

Initially the stopwatch is stopped and the timer reads 0 seconds. Given a sequence of times that the stopwatch button is pressed, determine what the stopwatch’s timer displays.

#### Input

The first line of input contains a single integer N (1≤N≤1000), which is the number of times the stopwatch was pressed.

The next N lines describe the times the stopwatch’s button was pressed in increasing order. Each line contains a single integer t (0≤t≤106), which is the time the button was pressed. No two button presses happen on the same second.

#### Output

Display still running if the stopwatch’s timer is still running after all button presses were made. Otherwise display the number of seconds displayed on the timer of tne stopwatch.

2

7

11

4

5

2

5

9

10

17

still running

4

0

2

104

117

15

## Solution of Stopwatch in java:–

```import java.util.*;
import java.lang.*;
import java.io.*;

public class Main
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc = new Scanner(System.in);
int n= sc.nextInt();

int totalTime= 0;
int[] times= new int[n];

for(int i=0; i<n; i++)
{
times[i]=sc.nextInt();
}

if(n%2!=0)
{
System.out.println("still running");
}
else{
for(int i=0; i<n; i=i+2)
{

totalTime=totalTime+(times[i+1]-times[i]);
}

System.out.println(totalTime);
}
}
}```