Staircase in java

In this question you need to write a program that prints a staircase of size ‘n’.

This is a staircase of size n=4:

    #
   ##
  ###
 ####

Its base and height are both equal to n. It is drawn using # symbols and spaces. The last line is not preceded by any spaces.

Write a program that prints a staircase of size n.

Input

A single integer, n, denoting the size of the staircase.

Output

Print a staircase of size n using # symbols and spaces.

Note: The last line must not have spaces in it.

Sample Input

6

Sample Output

     #
    ##
   ###
  ####
 #####
######

Explanation

The staircase is right-aligned, composed of # symbols and spaces, and has a height and width of n=6. You might notice, first line has 5 spaces (n-1) followed by 1 # and the last line has 0 spaces (n-n) and 6 # (n)

Solution:–

import java.util.*;
import java.lang.*;
import java.io.*;

public class Main
{
	public static void main (String[] args) throws java.lang.Exception
	{
     
		//your code here
     Scanner scanner = new Scanner(System.in);
      int x= scanner.nextInt();
       int row=x;
      
      for(int i=1;i<=row;i++)
        {
          for(int j=1;j<=row-i;j++)
            {
                System.out.print(" ");
            }

          for(int k=1;k<=i;k++)
            {
              System.out.print("#");
            }
          System.out.println();
            
        }
	
	}
}