A common problem in mathematics is to determine which quadrant a given point lies in. There are four quadrants, numbered from 1 to 4, as shown in the diagram below:

For example, the point A, which is at coordinates (12,5) lies in quadrant 1 since both its x and y values are positive, and point B lies in quadrant 2 since its x value is negative and its y value is positive.

Your job is to take a point and determine the quadrant it is in. You can assume that neither of the two coordinates will be 0.

### Input

The input consists of two lines.

The first line of input denotes the `x` coordinate.

The second line of input denotes the `y` coordinate.

### Output

Output the quadrant number (1, 2, 3 or 4) for the point (x,y).

Input

```10
6
```

Output

```1
```

Input

```9
-13
```

Output

```4
```

### Constraints

-109 <= x,y <= 109

## Solution of Quadrants in java:–

```import java.util.*;
import java.lang.*;
import java.io.*;

public class Main
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc = new Scanner(System.in);
int a,b;
a = sc.nextInt();
b = sc.nextInt();
if(a > 0 && b > 0)
System.out.print("1");
else if(a < 0 && b > 0)
System.out.print("2");
else if(a < 0 && b < 0)
System.out.print("3");
else
if(a > 0 && b < 0)
System.out.print("4");

}
}```