A common problem in mathematics is to determine which quadrant a given point lies in. There are four quadrants, numbered from 1 to 4, as shown in the diagram below:

For example, the point A, which is at coordinates (12,5) lies in quadrant 1 since both its x and y values are positive, and point B lies in quadrant 2 since its x value is negative and its y value is positive.

Your job is to take a point and determine the quadrant it is in. You can assume that neither of the two coordinates will be 0.

### Input

The input consists of two lines.

The first line of input denotes the `x`

coordinate.

The second line of input denotes the `y`

coordinate.

### Output

Output the quadrant number (1, 2, 3 or 4) for the point (x,y).

### Example 1

**Input**

10 6

**Output**

1

### Example 2

**Input**

9 -13

**Output**

4

### Constraints

-10^{9} <= x,y <= 10^{9}

## Solution of Quadrants in java:–

import java.util.*; import java.lang.*; import java.io.*; public class Main { public static void main (String[] args) throws java.lang.Exception { //your code here Scanner sc = new Scanner(System.in); int a,b; a = sc.nextInt(); b = sc.nextInt(); if(a > 0 && b > 0) System.out.print("1"); else if(a < 0 && b > 0) System.out.print("2"); else if(a < 0 && b < 0) System.out.print("3"); else if(a > 0 && b < 0) System.out.print("4"); } }

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