## Bubble Sort Problem

Consider the following version of Bubble Sort:

``````for (int i = 0; i < n; i++) {
for (int j = 0; j < n - 1; j++) {
// Swap adjacent elements if they are in decreasing order
if (a[j] > a[j + 1]) {
swap(a[j], a[j + 1]);
}
}
}
``````
1. `Array is sorted in numSwaps swaps.`, where numSwaps is the number of swaps that took place.
2. `First Element: firstElement`, where firstElement is the first element in the sorted array.
3. `Last Element: lastElement`, where lastElement is the last element in the sorted array.

Hint: To complete this challenge, you must add a variable that keeps a running tally of all swaps that occur during execution.

Given an array of integers, sort the array in ascending order using the Bubble Sort algorithm above. Once sorted, print the following three lines:

Example
[6,4,1]

``````swap    a
0       [6,4,1]
1       [4,6,1]
2       [4,1,6]
3       [1,4,6]

``````

The steps of the bubble sort are shown above. It took 3 swaps to sort the array. Output is:

Array is sorted in 3 swaps.
First Element: 1
Last Element: 6

Function Description

Complete the function countSwaps in the editor below.

countSwaps has the following parameter(s):

• int a[n]: an array of integers to sort

Prints

Print the three lines required, then return. No return value is expected.

Input Format

The first line contains an integer, n , the size of the array a.
The second line contains n space-separated integers a[i] .

Constraints 2<=n<=600 1<=a[i]<=2X10^6

Output Format

Sample Input 0

``````STDIN   Function
-----   --------
3       a[] size n = 3
1 2 3   a = [1, 2, 3]

``````

Sample Output 0

``````Array is sorted in 0 swaps.
First Element: 1
Last Element: 3

``````

Explanation 0
The array is already sorted, so 0 swaps take place.

Sample Input 1

``````3
3 2 1
``````

Sample Output 1

``````Array is sorted in 3 swaps.
First Element: 1
Last Element: 3

``````

Explanation 1
The array is not sorted, and its initial values are:{3,2,1} . The following 3 swaps take place: 1.{3,2,1}->{2,3,1} 2.{2,3,1}->{2,1,3} 3.{2,1,3}->{1,2,3}

At this point the array is sorted and the three lines of output are printed to stdout.

## Solution of Bubble Sort Problem:–

``````import java.util.*;
import java.lang.*;
import java.io.*;

public class Main
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();

int arr[]= new int[n];
for(int i=0;i<n;i++)
{
arr[i]=sc.nextInt();
}
int swap=0;
for(int i=0;i<n;i++)
{
for(int j=0;j<n-1-i;j++)
{
if(arr[j]>arr[j+1])
{
int temp=arr[j];
arr[j]=arr[j+1];
arr[j+1]=temp;
swap++;
}
}
}

System.out.println("Array is sorted in "+ swap +" swaps.");
System.out.println("First Element: "+arr);
System.out.println("Last Element: "+arr[n-1]);

}
}``````