You are given a chessboard of size N x N, where the top left square is black. Each square contains a value. Find the sum of values of all black square and all white squares.

Remember that in a chessboard black and white squares alternate. Input User task: Input consists on N and the the numbers in the NxN matrix. You need to print out the sum of black squares and then white squares in the next line.

#### Constraints:-

```
1 <= N <= 1000
1 <= Matrix[i][j] <= 100000
```

#### Output

Print two lines, first line containing the sum of black squares and second line containing the sum of white squares.

### Example

#### Input:

```
3
1 2 3
4 5 6
7 8 9
```

#### Output:

```
25
20
```

##### Explanation:-

black square contains 1, 3, 5, 7, 9; sum = 25

white square contains 2, 4, 6, 8; sum = 20

## Solution of Alt matrix sum :–

import java.util.*; import java.lang.*; import java.io.*; public class Main { public static void main (String[] args) throws java.lang.Exception { //your code here Scanner sc = new Scanner(System.in); int n = sc.nextInt(); int arr[][] = new int[n][n]; for(int i=0;i<arr.length;i++) { for(int j=0;j<arr[i].length;j++) { arr[i][j]=sc.nextInt(); } } int sum=0,temp=0; for(int i=0;i<arr.length;i++) { for(int j=0;j<arr[i].length;j++) { if((i+j)%2==0) { sum=sum+arr[i][j]; } else{ temp=temp+arr[i][j]; } } } System.out.println(sum); System.out.println(temp); } }

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